16x^2+224x-1323=0

Solution for 16x^2+224x-1323=0 equation:

16x^2+224x-1323=0

a = 16; b = 224; c = -1323;
Δ = b2-4ac
Δ = 2242-4·16·(-1323)
Δ = 134848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{134848}=\sqrt{3136*43}=\sqrt{3136}*\sqrt{43}=56\sqrt{43}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(224)-56\sqrt{43}}{2*16}=\frac{-224-56\sqrt{43}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(224)+56\sqrt{43}}{2*16}=\frac{-224+56\sqrt{43}}{32}
$